How do you find the zeros, real and imaginary, of #y=x^24x12# using the quadratic formula?Calculus Graph 4xy^2=12 4x y2 = 12 4 x y 2 = 12 Subtract y2 y 2 from both sides of the equation 4x = 12− y2 4 x = 12 y 2 Divide each term by 4 4 and simplify Tap for more steps Divide each term in 4 x = 12 − y 2 4 x = 12 y 2 by 4 4 4 x 4 = 12 4 − y 2 4 4 x 4 = 12 4 y 2Show What You Know Week 18 Name_____ Date_____ Grade_____ °
Solution What Are The Solutions To The Equation Y X 3 3x 2 4x 12
